Deshaun Watson named AFC Offensive Player of the Week

Photo by Tim Warner/Getty Images
Photo by Tim Warner/Getty Images /

Houston Texans’ rookie quarterback Deshaun Watson has been rewarded for another great game.

The NFL announced on Wednesday that Houston Texans’ quarterback Deshaun Watson has been named the AFC Offensive Player of the Week for his week four performance against the Tennessee Titans that led to a 57-14 win.

Watson finished the game with 283 yards, four touchdowns and one interception through the air. He completed an astonishing 73.5 percent of his passes. Watson also ran for 24 yards and one touchdown on the ground.

On Wednesday, Watson was asked about being named the AFC offensive player of the week.

Watson has now proven that he can play well against bad defenses after taking advantage of the Cincinnati Bengals, New England Patriots and Tennessee Titans. His first real test will come this Sunday night against the Kansas City Chiefs.

As talented as the Chiefs are on defense, they’re currently giving up 248 yards through the air per game. That ranks them 25th in the NFL in pass defense. But their pass rush has racked up 11 sacks in four games.

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While the Texans’ offensive line has looked better over the past two weeks, they will have their hands full with the likes of Justin Houston.

Thankfully, Watson has the ability to make plays if his offensive line breaks down in pass protection. This will certainly something to watch out for in week five.

Comment below and gives us your thoughts on Watson winning the AFC Offensive Player of the Week award. Also will he continue to to play well against the Chiefs?